Question

Coffee that sells for $7.20/kg is mixed with coffee that sells for $4.80/kg to make 600kg of coffee that will sell for $5.60/kg. How many kilograms of each was used. Solve using elimination

Answer 1

200kg

Explanation:

Let's assume x represents the amount of coffee that sells for $7.20/kg, and y represents the amount of coffee that sells for $4.80/kg.

We have two equations based on the given information:

Equation 1: x + y = 600 (total weight of coffee)

Equation 2: (7.20x + 4.80y) / 600 = 5.60 (average price per kilogram)

To solve this system of equations using elimination, we can multiply equation 1 by 4.80 and equation 2 by 600 to eliminate the decimals.

4.80 * (x + y) = 4.80 * 600

7.20x + 4.80y = 5.60 * 600

Simplifying:

4.80x + 4.80y = 2880

7.20x + 4.80y = 3360

Now, subtract equation 1 from equation 2:

(7.20x + 4.80y) - (4.80x + 4.80y) = 3360 - 2880

7.20x - 4.80x = 480

2.40x = 480

x = 480 / 2.40

x = 200

Substituting x = 200 into equation 1:

200 + y = 600

y = 600 - 200

y = 400

Therefore, 200 kg of coffee that sells for $7.20/kg and 400 kg of coffee that sells for $4.80/kg were used to make the 600 kg of coffee that sells for $5.60/kg.

Hope This Helps!