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How much energy is required to heat 15 grams of ice at -20 degrees celsius to 120 degrees celsius of steam

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Answer: approximately 46,415 Joules of energy

Step-by-step explanation:

Heating the ice to its melting point (0 degrees Celsius):

The specific heat capacity of ice is approximately 2.09 J/g°C.

The temperature change required is 0°C - (-20°C) = 20°C.

The energy required to heat the ice to 0 degrees Celsius is:

Energy = mass × specific heat capacity × temperature change

= 15 g × 2.09 J/g°C × 20°C

= 626 J

Melting the ice at 0 degrees Celsius:

The heat of fusion (enthalpy of fusion) for ice is approximately 334 J/g.

The energy required to melt the ice is:

Energy = mass × heat of fusion

= 15 g × 334 J/g

= 5010 J

Heating the water from 0 degrees Celsius to 100 degrees Celsius:

The specific heat capacity of water is approximately 4.18 J/g°C.

The temperature change required is 100°C - 0°C = 100°C.

The energy required to heat the water is:

Energy = mass × specific heat capacity × temperature change

= 15 g × 4.18 J/g°C × 100°C

= 6270 J

Vaporizing the water at 100 degrees Celsius:

The heat of vaporization (enthalpy of vaporization) for water is approximately 2260 J/g.

The energy required to vaporize the water is:

Energy = mass × heat of vaporization

= 15 g × 2260 J/g

= 33,900 J

Heating the steam from 100 degrees Celsius to 120 degrees Celsius:

The specific heat capacity of steam is approximately 2.03 J/g°C.

The temperature change required is 120°C - 100°C = 20°C.

The energy required to heat the steam is:

Energy = mass × specific heat capacity × temperature change

= 15 g × 2.03 J/g°C × 20°C

= 609 J

The total energy required is the sum of all the individual steps:

Total energy = Energy of step 1 + Energy of step 2 + Energy of step 3 + Energy of step 4 + Energy of step 5

= 626 J + 5010 J + 6270 J + 33,900 J + 609 J

= 46,415 J

Therefore, it would require approximately 46,415 Joules of energy to heat 15 grams of ice at -20 degrees Celsius to 120 degrees Celsius of steam.

User Ranjit Kumar
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