Question

What is the inverse of the function f(x)=2x+1 ? h(x)=(1)/(2)x-(1)/(2) h(x)=(1)/(2)x+(1)/(2) h(x)=(1)/(2)x-2 h(x)=(1)/(2)x+2 Mark this and return Save and Exit

Answer 1

h(x) =
`(1)/(2)` x -
`(1)/(2)`

Explanation:

let y = f(x) and rearrange making x the subject

y = 2x + 1 ( subtract 1 from both sides )

y - 1 = 2x ( divide both sides by 2 )

`(y-1)/(2)` = x

change y back into terms of x with x = h(x) , that is

h(x) =
`(x-1)/(2)` =
`(1)/(2)` x -
`(1)/(2)`