Question

64. Electricity: How many volts of electricity would Marcia need to produce 48 Omega of resistance from a 300 watt lamp?

Answer 1

120 V

Step-by-step explanation:

V = ?

P = 300 W

R = 48 Ω

P = V² / R

V² = PR = (300 W)(48 Ω) = 14,400

V = √14,400 = 120 V