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If two of the zeroes of the polynomial P(x)=2x^(3)-x^(2)-7x+6 are (3)/(2) and -2 the other zero will be

User Eshaham
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1 Answer

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Answer:

Explanation:

The given equation is p(x)=
2x^3-x^2-7x+6 of the form
ax^3+bx^2+cx+d

and the zeroes are:

α=3/2 and β= -2

We have to find the third zero let say "γ".

p(x)=
2x^3-x^2-7x+6

∴ a=2, b=1, c=-7 and d=6

Then αβγ=
\cfrac{-d}{a}


(\cfrac{3}{2}) (-2)·γ=
\cfrac{-6}{2}

⇒ -3γ= -3

⇒γ=1

Therefore, the third zero of
2x^3-x^2-7x+6 is 1.

User Paul Westcott
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