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Find three consecutive integers if thrice the third less 10 is equal to the sum of the first and the second. Find the SECOND integer.

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Answer:

second integer = 6

Explanation:

let the three consecutive integers be n , n + 1 , n + 2

the thrice the third less 10 is 3(n + 2) - 10 , so

3(n + 2) - 10 = n + n + 1

3n + 6 - 10 = 2n + 1

3n - 4 = 2n + 1 ( subtract 2n from both sides )

n - 4 = 1 ( add 4 to both sides )

n = 5

n + 1 = 5 + 1 = 6

n + 2 = 5 + 2 = 7

the three consecutive integers are 5 , 6 , 7

with the second integer 6

User Champer Wu
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