Answer:
second integer = 6
Explanation:
let the three consecutive integers be n , n + 1 , n + 2
the thrice the third less 10 is 3(n + 2) - 10 , so
3(n + 2) - 10 = n + n + 1
3n + 6 - 10 = 2n + 1
3n - 4 = 2n + 1 ( subtract 2n from both sides )
n - 4 = 1 ( add 4 to both sides )
n = 5
n + 1 = 5 + 1 = 6
n + 2 = 5 + 2 = 7
the three consecutive integers are 5 , 6 , 7
with the second integer 6