Question

Given that integer array x has elements 5, 10, 15, 20, what is the output?

int i;

for (i = 0; i < 4; ++i) {

System.out.print(x[i] + x[i + 1]);

}
Given that integer array x has elements 5, 10, 15, 20, what is the output?

int i;

for (i = 0; i < 4; ++i) {

System.out.print(x[i] + x[i + 1]);

}
15, 25, 35, 20

10, 15, 20, 5

Out of range access

15, 25, 35, 25

Answer 1

The given code outputs 15, 25, 35, Out of range access.

Step-by-step explanation:

The given code snippet is written in the programming language Java. It defines an integer array x with elements 5, 10, 15, and 20. Then, it initializes an integer variable i to 0 and runs a for loop where i goes from 0 to 3 (i < 4).

Inside the loop, the code prints the sum of x[i] and x[i + 1] using the System.out.print function. For each iteration, it prints the sum of the current element and the next element of the array.

The output of the code will be:

1. 15 (5 + 10)
2. 25 (10 + 15)
3. 35 (15 + 20)
4. Out of range access (20 is added to a non-existent element)

Answer 2

The output of the code snippet will be: "15 25 35".

The for loop loops through the members of the integer array x, beginning at index 0 and ending at index 3 (4 elements total). System.out.print(x[i] + x[i + 1]) outputs the sum of the current element x[i] and the next element x[i + 1] within the loop.

It adds 5 and 10 for the first iteration (i = 0), yielding 15. The second iteration (i = 1) adds 10 and 15, yielding 25. It adds 15 and 20 for the third iteration (i = 2), yielding 35. Because the loop ends when i = 4, the fourth iteration (i = 3) is skipped.