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Find (k∘k)(−2)for k(x)=2x2+2x−3.

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3 votes

Answer:

To find
(k∘k)(−2) for k(x)=2x^2+2x−3, we first need to evaluate
k(-2):


k(-2) = 2(-2)^2 + 2(-2) - 3 = 8 - 4 - 3 = 1

Next, we need to evaluate
k(1) since it is the input for the second application of k in
(k∘k)(-2):


k(1) = 2(1)^2 + 2(1) - 3 = 2 + 2 - 3 = 1

Finally, we can evaluate
(k∘k)(-2) using the composition of functions formula:


(k∘k)(-2) = k(k(-2)) = k(1) = 1

Therefore,
(k∘k)(-2) = 1.


Hope
it
helps!

User Chriszumberge
by
9.3k points

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