Question

Find the equation of a line that is perpendicular to the line y=\frac{1}{3} x+5 and contains the point (-7,0) y=\quad (Type your answer in slope-intercept form.)

Answer 1

`y=-3x-21`

Explanation:

`y=(1)/(3)x+5` point:
`(-7,0)`

Step 1. Find the negative reciprocal of the slope

Slope =
`(1)/(3)`

The reciprocal of the slope is the inverse

Thus, the reciprocal is -3

Using the slope, plug in the point to the equation to find its perpendicular line

`0=-3(-7)+b`

`0=21+b`

`b=-21`

The equation is
`y=-3x-21`