112k views
4 votes
For the point P(−7,3) and Q(−2,8), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.

User Yacovm
by
8.5k points

1 Answer

3 votes

Answer:

d(P, Q) = 7.071067812

M = (-4.5, 5.5)

Explanation:

Finding the distance d(P, Q):

We can find the distance between two points using the distance formula, which is given by:

d = √[(x2 - x1)^2 + (y2 - y1)^2], where

  • (x1, y1) is one point,
  • and (x2, y2) is another point.

Thus, we can find d, the distance, of P and Q by plugging in P(-7, 3) for (x1, y1) and Q(-2, 8) for (x2, y2):

d = √[(-2 - (-7))^2 + (8 -3)^2]

d = √[(-2 + 7)^2 + (5)^2]

d = √[(-5)^2 + 25]

d = √[25 + 25]

d = √[50]

d = 7.071067812

Thus, the distance, d, between P and Q is 7.071067812 units.

If you prefer to simply use √(50) units for the distance, you can do so since its the same as 7.071067812.

Finding the midpoint:

We can find the midpoint between two points using the midpoint formula, which is given by:

M = (x1 + x2) / 2, (y1 + y2) / 2

Thus, we can find M, the midpoint of the segment PQ by plugging in P(-7, 3) for (x1, y1) and Q(-2, 8) for (x2, y2) in the midpoint formula:

M = (-7 + -2) / 2, (3 + 8) / 2

M = (-9) / 2, (11) / 2

M = (-4.5, 5.5)

Therefore, the coordinates of the midpoint of the segment PQ are (-4.5, 5.5)

User Nerius Jok
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories