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For the point P(−7,3) and Q(−2,8), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.

User Yacovm
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1 Answer

3 votes

Answer:

d(P, Q) = 7.071067812

M = (-4.5, 5.5)

Explanation:

Finding the distance d(P, Q):

We can find the distance between two points using the distance formula, which is given by:

d = √[(x2 - x1)^2 + (y2 - y1)^2], where

  • (x1, y1) is one point,
  • and (x2, y2) is another point.

Thus, we can find d, the distance, of P and Q by plugging in P(-7, 3) for (x1, y1) and Q(-2, 8) for (x2, y2):

d = √[(-2 - (-7))^2 + (8 -3)^2]

d = √[(-2 + 7)^2 + (5)^2]

d = √[(-5)^2 + 25]

d = √[25 + 25]

d = √[50]

d = 7.071067812

Thus, the distance, d, between P and Q is 7.071067812 units.

If you prefer to simply use √(50) units for the distance, you can do so since its the same as 7.071067812.

Finding the midpoint:

We can find the midpoint between two points using the midpoint formula, which is given by:

M = (x1 + x2) / 2, (y1 + y2) / 2

Thus, we can find M, the midpoint of the segment PQ by plugging in P(-7, 3) for (x1, y1) and Q(-2, 8) for (x2, y2) in the midpoint formula:

M = (-7 + -2) / 2, (3 + 8) / 2

M = (-9) / 2, (11) / 2

M = (-4.5, 5.5)

Therefore, the coordinates of the midpoint of the segment PQ are (-4.5, 5.5)

User Nerius Jok
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