Question

What is the solution to the system of equations below? y = negative one-third x + 9 and y = two-thirds x minus 12 (21, 2) (21, –10) (–21, 16) (–21, –26)

Answer 1

To find the solution to the system of equations, we need to find the values of x and y that satisfy both equations simultaneously.

Given the equations:

1. y = -1/3x + 9

2. y = 2/3x - 12

We can solve the system by setting the two equations equal to each other:

-1/3x + 9 = 2/3x - 12

Now, we can solve for x:

-1/3x - 2/3x = -12 - 9

-3/3x = -21

x = -21

To find the value of y, we substitute the value of x into either of the original equations. Let's use the first equation:

y = -1/3(-21) + 9

y = 7 + 9

y = 16

Therefore, the solution to the system of equations is (-21, 16).

Note: The other answer choices provided (21, 2), (21, -10), and (-21, -26) are not the correct solutions to the given system of equations

Answer 2

Explanation:

y=-1/3(x=9)

y=2/3x-12

-x/3-9/3=2x/3-12

-9/3=12=2x/3+x/3

27/3=3x/3

9=x

y=-1/3(9+9)

y=-6

y=2/3x9-12

y=-6