92.7k views
2 votes
What is the solution to the system of equations below? y = negative one-third x + 9 and y = two-thirds x minus 12 (21, 2) (21, –10) (–21, 16) (–21, –26)

User Willk
by
8.2k points

2 Answers

4 votes

To find the solution to the system of equations, we need to find the values of x and y that satisfy both equations simultaneously.

Given the equations:

1. y = -1/3x + 9

2. y = 2/3x - 12

We can solve the system by setting the two equations equal to each other:

-1/3x + 9 = 2/3x - 12

Now, we can solve for x:

-1/3x - 2/3x = -12 - 9

-3/3x = -21

x = -21

To find the value of y, we substitute the value of x into either of the original equations. Let's use the first equation:

y = -1/3(-21) + 9

y = 7 + 9

y = 16

Therefore, the solution to the system of equations is (-21, 16).

Note: The other answer choices provided (21, 2), (21, -10), and (-21, -26) are not the correct solutions to the given system of equations

User Datta
by
7.8k points
3 votes

Answer:

Explanation:

y=-1/3(x=9)

y=2/3x-12

-x/3-9/3=2x/3-12

-9/3=12=2x/3+x/3

27/3=3x/3

9=x

y=-1/3(9+9)

y=-6

y=2/3x9-12

y=-6

User Joe Lu
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories