Question

if 10.0 ml of a 10.0 m stock solution of naoh is diluted to 250 ml, what is the concentration of the resulting stock solution?

Answer 1

Answer: 0.400M

Step-by-step explanation:

`m_(1)`= 10.0M

`m_(2)`= ?

`v_(1)`= 10.0mL

`v_(2)`= 250mL

To find
`m_(2)`(the concentration of the resulting stock solution):

1)
`m_(1)`
`v_(1)`=
`m_(2)`
`v_(2)`

divide
`v_(2)` into both sides

2)
`m_(2)`=
`m_(1)`
`v_(1)` /
`v_(2)`

substitute

3)
`m_(2)`= (10.0M)(10.0mL) / (250mL)

solve the equation

4)
`m_(2)`= 0.400M