Question

Find three conrecutive integers so the sum of the first three is two more than the twice the fourth.

Answer 1

The consecutive integers are 4, 5, and 6.

Explanation:

The problem starts with "three consecutive integers," but then mentions a fourth. We'll assume 4 consecutive integers.

Let the first integer be x. The next three would be (x+1), (x+2), and (x+3)

". . . the sum of the first three is two more than the twice the fourth."

x + (x+1) + (x+2) > 2(x+3)

3x+3>2x+6

x>3

x must be greater than 3 to satisfy this inequality. The nearest integer greater than 3 is 4.

For x = 4:

4+5+6 > 2*4+6 ?

15 > 14? YES