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assume x is a particular real number and use de morgan’s laws to write negations for the statement 2>x>-10

User Onit
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1 Answer

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2 > x > -10 is equivalent to
x < 2 \wedge x > -10.

One of the de Morgan's Laws is
\\eg (p \wedge q)\Leftrightarrow \\eg p\vee \\eg q.

Therefore, we can write


\\eg (2 > x > -10)\Leftrightarrow \\eg(x < 2) \vee \\eg(x > -10) \Leftrightarrow x > 2 \vee x < -10

User Dulaj Kulathunga
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