Question

)According to an observer (A) on Earth; A spaceship carrying another observer (8)

goes to a planet with the speed of 0.8c and arrives to a planet in 30 years.
a. How far is the planet according to the observer on Earth (A)?
b. What is the travel duration according to the observer in the spaceship (B)?

Answer 1

A) As speed = distance/time

here also speed = 0.8c

time = 30 years

so, distance = speed x time

= 0.8c x30

= 24c years

B) T =T0 /√1+(v2/c2)

so, T = 30/1.28

23.42 years

Step-by-step explanation:

By special theory of relativity we can see the variation between the values of distance and time by observer moving at velocity comparable to the speed of light and when this happens then the formulae applies.