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Show that lines x-3y = 6 and 4y = 12x are perpendicular

User MiniQuark
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2 Answers

1 vote

Answer:

Explanation:

Given equations are: y= x/3 -2 and y=3x

Slope of 1st equation : 1/3

The slope of 2nd equation: 3

Here, the slope of the 1st equation is the inverse of the 2nd equation.

Therefore both lines are perpendicular to each other.

User Blenikos
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5 votes

Perpendicular lines

By definition, perpendicular lines are two lines that cross at a 90° angle. If two lines are perpendicular, their slopes are negative inverses of one another. Let's say that line A is perpendicular to line B, and A's slope is 2. Then, B's slope would be -1/2.

The problem is asking us to show that lines x - 3y = 6 and 4y = 12x are perpendicular. Well, to make the decision, we first need to write both of these in slope-intercept form.

slope-intercept form

The format of slope-intercept equations is y = mx + b (m = slope and b = y-intercept).

So we need to write x - 3y = 6 in y = mx + b.

-3y = 6 - x

-3y = -x + 6

3y = -x - 6

y = x/3 - 6/3

y = x/3 - 2

Now, the second equation:

4y = 12x

y = 3

The lines aren't perpendicular since their slopes are not negative inverses of one another.

User Takeya
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7.7k points

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