Question

Given the data listed below, provide amount of phosphoric acid (85% soln) in mmoles that would be present in this reaction. Please provide your answer to 4 decimal places and only include the number. Volume of phosphoric acid: 0.1 mL Density of phosphoric acid: 1.685 g/mL Molecular weight of phosphoric acid: 98 g/mol

Answer 1

The amount of 85% phosphoric acid solution present in the reaction is 1.4609 millimoles (mmol) when calculated from the given volume, density, and molecular weight of the acid.

Step-by-step explanation:

To calculate the amount of phosphoric acid in millimoles (mmoles) present in the reaction, we need to first determine the mass of the phosphoric acid solution given its volume and density, and then we can find the moles of phosphoric acid using its molecular weight. However, since we have an 85% solution, we must account for this concentration. Here are the steps:

• Calculate the mass of the 85% phosphoric acid solution: 0.1 mL × 1.685 g/mL = 0.1685 g.
• Determine the mass of pure phosphoric acid: 0.1685 g × 0.85 = 0.143225 g.
• Convert the mass of phosphoric acid to moles: 0.143225 g ÷ 98 g/mol = 0.0014609 mol.
• Finally, convert moles to millimoles: 0.0014609 mol × 1000 mmol/mol = 1.4609 mmol.

The amount of phosphoric acid (85% solution) present in the reaction is 1.4609 mmol to four decimal places.

Answer 2

There are approximately 1.717 millimoles of phosphoric acid (85% solution) present in this reaction.

To calculate the amount of phosphoric acid (H3PO4) in millimoles (mmoles) present in this reaction, you can use the following information:

- Volume of phosphoric acid: 0.1 mL

- Density of phosphoric acid: 1.685 g/mL

- Molecular weight of phosphoric acid: 98 g/mol

First, let's calculate the mass of the phosphoric acid solution:

Mass = Volume × Density

Mass = 0.1 mL × 1.685 g/mL

Mass ≈ 0.1685 grams

Now, we need to convert this mass to moles using the molecular weight:

Moles = Mass / Molecular Weight

Moles = 0.1685 g / 98 g/mol

Moles ≈ 0.001717 moles

To express this in millimoles, multiply by 1000:

Millimoles ≈ 0.001717 moles × 1000

Millimoles ≈ 1.717 millimoles

So, there are approximately 1.717 millimoles of phosphoric acid (85% solution) present in this reaction.