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3 votes
A manufacturer sells a piece of aluminum that is

5.50cm wide. A student measured it to be 5.33cm wide. What is the
percent error of the student's measurement?
A) 3.1%
B) 3.2%
Help, please!
A manufacturer sells a piece of aluminum that is 5.50{~cm} wide. A student measured it to be 5.33{~cm} wide. What is the percent error of the student's measurement?

User Veron
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1 Answer

4 votes

Answer:

percent error of the student's measurement

[(5.50-5.33)/5.33]×100=3,189..=3.2%

Explanation:

User Leonid Makarov
by
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