Question

What volume of a 1.40MHCl solution should you use to prepare 3.00 L of a 0.050MHCl solution? 3.00 L 0.107 L 0.210 L 84.0 L

Answer 1

To determine the volume of a 1.40 M HCl solution needed to prepare 3.00 L of a 0.050 M HCl solution, we can use the equation:

M1V1 = M2V2

Where:

M1 = initial concentration of the HCl solution

V1 = volume of the HCl solution to be used

M2 = final concentration of the HCl solution

V2 = final volume of the HCl solution

Given:

M1 = 1.40 M

V1 = ?

M2 = 0.050 M

V2 = 3.00 L

Substituting these values into the equation:

(1.40 M)(V1) = (0.050 M)(3.00 L)

Solving for V1:

V1 = (0.050 M)(3.00 L) / 1.40 M

Calculating this expression gives:

V1 ≈ 0.107 L

Therefore, you should use approximately 0.107 L (or 107 mL) of the 1.40 M HCl solution to prepare 3.00 L of a 0.050 M HCl solution.