Answer and Explanation:
In a 0.700 M solution of Sr(OH)2, the value of [OH-] can be determined by considering the stoichiometry of the compound.
Sr(OH)2 is a strong base that dissociates completely in water, producing two OH- ions for every one formula unit of Sr(OH)2.
Therefore, the concentration of OH- ions in the solution will be twice the molarity of Sr(OH)2.
Given that the molarity (M) of the Sr(OH)2 solution is 0.700 M, we can calculate the concentration of OH- as follows:
[OH-] = 2 * (0.700 M)
[OH-] = 1.400 M
Therefore, the value of [OH-] in a 0.700 M solution of Sr(OH)2 is 1.400 M.