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What is the value of [OH–] in a 0.700 M solution of Sr(OH)2?
M=

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Answer and Explanation:

In a 0.700 M solution of Sr(OH)2, the value of [OH-] can be determined by considering the stoichiometry of the compound.

Sr(OH)2 is a strong base that dissociates completely in water, producing two OH- ions for every one formula unit of Sr(OH)2.

Therefore, the concentration of OH- ions in the solution will be twice the molarity of Sr(OH)2.

Given that the molarity (M) of the Sr(OH)2 solution is 0.700 M, we can calculate the concentration of OH- as follows:

[OH-] = 2 * (0.700 M)

[OH-] = 1.400 M

Therefore, the value of [OH-] in a 0.700 M solution of Sr(OH)2 is 1.400 M.

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