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Let f(x)=4 x+5 . Then the equation of the tangent line to the graph of f(x) at the point (-1,1) is y=

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Answer and Step-by-step explanation:

The equation of the tangent line to the graph of a function at a given point can be found using the point-slope form of a line. The slope of the tangent line is equal to the derivative of the function at that point. Since f(x) = 4x + 5, its derivative f’(x) = 4. So, the slope of the tangent line at x = -1 is 4.

Using the point-slope form, we have y - y1 = m(x - x1), where (x1, y1) is the given point (-1, 1) and m is the slope 4. Substituting these values, we get y - 1 = 4(x + 1). Simplifying this equation, we get y = 4x + 5.

So, the equation of the tangent line to the graph of f(x) at the point (-1, 1) is y = 4x + 5.

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