Answer and Step-by-step explanation:
The product of (3b+7)(3b-7) can be found by using the formula for the difference of two squares, which states that a^2 - b^2 = (a+b)(a-b). In this case, a = 3b and b = 7, so the product is (3b)^2 - 7^2 = 9b^2 - 49. So, the product of (3b+7)(3b-7) in standard form is 9b^2 - 49.