Answer: 12.004 grams of NO would be produced.
Step-by-step explanation:
To determine the amount of nitrogen monoxide (NO) produced in grams, we need to use stoichiometry and the given balanced chemical equation:
4NH3 + 5O2 → 4NO + 6H2O
From the balanced equation, we can see that 5 moles of O2 react with 4 moles of NH3 to produce 4 moles of NO. This means that the mole ratio of O2 to NO is 5:4.
If 0.5 moles of O2 reacted, we can use this mole ratio to calculate the amount of NO produced:
0.5 moles O2 x (4 moles NO / 5 moles O2) = 0.4 moles NO
Now we need to convert moles of NO to grams using its molar mass. The molar mass of NO is 30.01 g/mol.
0.4 moles NO x 30.01 g/mol = 12.004 g NO
Therefore, if 0.5 moles of O2 reacted, 12.004 grams of NO would be produced.