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Given the reaction between 4Nh3+5O2->4NO +6H20. What is the amount of nitrogen monoxide produced in grams if 0.5 of Oxygen reacted

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Answer: 12.004 grams of NO would be produced.

Step-by-step explanation:
To determine the amount of nitrogen monoxide (NO) produced in grams, we need to use stoichiometry and the given balanced chemical equation:

4NH3 + 5O2 → 4NO + 6H2O

From the balanced equation, we can see that 5 moles of O2 react with 4 moles of NH3 to produce 4 moles of NO. This means that the mole ratio of O2 to NO is 5:4.

If 0.5 moles of O2 reacted, we can use this mole ratio to calculate the amount of NO produced:

0.5 moles O2 x (4 moles NO / 5 moles O2) = 0.4 moles NO

Now we need to convert moles of NO to grams using its molar mass. The molar mass of NO is 30.01 g/mol.

0.4 moles NO x 30.01 g/mol = 12.004 g NO

Therefore, if 0.5 moles of O2 reacted, 12.004 grams of NO would be produced.

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