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Sill A bag of M&M's has 5 red, 6 green, 3 blue, and 2 yellow M&M's. What is the probability of randomly picking a. a yellow? Leave answer as a reduced fraction. b. a blue or green? c. an orange? 0 Submit Question RO​

User Desval
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1 Answer

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Answer:

below

Explanation:

a. To calculate the probability of randomly picking a yellow M&M, we need to consider the total number of M&M's and the number of yellow M&M's.

Total M&M's = 5 (red) + 6 (green) + 3 (blue) + 2 (yellow) = 16

Number of yellow M&M's = 2

Probability of picking a yellow M&M = Number of yellow M&M's / Total M&M's = 2/16 = 1/8

Therefore, the probability of randomly picking a yellow M&M is 1/8.

b. To calculate the probability of randomly picking a blue or green M&M, we need to consider the total number of M&M's and the number of blue and green M&M's.

Total M&M's = 5 (red) + 6 (green) + 3 (blue) + 2 (yellow) = 16

Number of blue M&M's = 3

Number of green M&M's = 6

Total blue and green M&M's = 3 + 6 = 9

Probability of picking a blue or green M&M = Number of blue and green M&M's / Total M&M's = 9/16

Therefore, the probability of randomly picking a blue or green M&M is 9/16.

c. The problem does not provide information about the number of orange M&M's. Therefore, we cannot calculate the probability of picking an orange M&M without this information.

User Monkey Monk
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