The volume of the mock-up tank is 6 times smaller than the actual tank. This means that the volume of the mock-up tank is 1/6th (or 16.67%) of the volume of the actual tank.
To understand this, let's consider an example.
Suppose the actual tank has a volume of 100 cubic units. If we make each dimension 6 times smaller, the dimensions of the mock-up tank would be 1/6th of the actual tank. This means the volume of the mock-up tank would be (1/6)^3 = 1/216 of the volume of the actual tank.
To find the percentage, we divide the volume of the mock-up tank by the volume of the actual tank and multiply by 100:
(1/216) * 100 = 0.463% (rounded to three decimal places).
So, the volume of the actual tank is approximately 0.463% of the volume of the mock-up tank.
Now, let's move on to the second question.
If you were to take a cross section parallel to the base of one of the holding tanks, the shape would be rectangular. Since the tank is described as a "holding tank," it is likely to have a rectangular shape with a flat base and vertical sides.
I hope this helps! Let me know if you have any further questions.