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Pls help asap plsssss​-example-1
User Eren
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To solve the equation x² + 12x - 11 = 0 graphically, you can draw a line on the graph of y = x² + 9x - 4.

Here's how you can do it step by step:

1. Start by graphing the equation y = x² + 9x - 4. This is a quadratic equation, so the graph will be a parabola.

2. To find the x-intercepts of the equation x² + 12x - 11 = 0, which are the solutions to the equation, you need to find the points where the graph of y = x² + 9x - 4 intersects the x-axis.

3. To do this, you can set y equal to 0 in the equation y = x² + 9x - 4 and solve for x. When y = 0, the equation becomes 0 = x² + 9x - 4.

4. Now, you can graph the line y = 0 on the same graph as y = x² + 9x - 4. This line represents the x-axis.

5. The points where the graph of y = x² + 9x - 4 intersects the x-axis are the solutions to the equation x² + 12x - 11 = 0.

6. Finally, you can write the equation of the line you drew as y = 0x + 0, or simply y = 0.

So, the line you should draw on the graph of y = x² + 9x - 4 to solve the equation x² + 12x - 11 = 0 graphically is y = 0.

By finding the x-intercepts of the graph of y = x² + 9x - 4, which correspond to the solutions of the equation x² + 12x - 11 = 0, you can visually solve the equation.

I hope you find this helpful. Please feel free to inquire upon any further questions or concerns if necessary.

User Joel Skrepnek
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