Question

An airplane maintaining a constant airspeed takes as long to travel 560 mi with the wind as it does to travel 400 mi against the wind. If the wind is blowing at ​20

mph, what is the rate of the plane in still​ air?

Answer 1

Explanation:

disatnce / rate = time

560/ (a+w) = t

400 / ( a-w) = t Since we know the 't' is the same , we can equate the two equations:

560 / (a+20) = 400/ ( a-20) <===== solve this equation for 'a'

a = 120 mph