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Minimize Q=6x^2+3y^2 , where x+y=9.

Minimize Q=6x^2+3y^2 , where x+y=9.-example-1
User Levininja
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2 Answers

5 votes

Answer:

The minimum value of Q is 162

(x=3 and y=6)

Explanation:

To minimize the function Q = 6x^2 + 3y^2, subject to the constraint x + y = 9, we can graphically analyze the problem.

First, we rewrite the constraint equation x + y = 9 as y = 9 - x. Now, we substitute this expression for y into the objective function Q:

Q = 6x^2 + 3(9 - x)^2

Q = 6x^2 + 3(81 - 18x + x^2)

Q = 6x^2 + 243 - 54x + 3x^2

Q = 9x^2 - 54x + 243

Now, we can plot the graph of Q as a quadratic function of x. The vertex of this parabolic curve represents the minimum value of Q within the given constraint.

By completing the square or finding the vertex using the formula x = -b/(2a), we can determine that the x-coordinate of the vertex is x = 3. Substituting this value back into the constraint equation, we find that y = 9 - 3 = 6.

Therefore, the minimum value of Q occurs when x = 3 and y = 6, which corresponds to the point (3, 6) on the graph.

Hope it helps!! :)

User Casenonsensitive
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5 votes

Q = 6x² + 3y² with y = 9 - x

Q = 6x² + 3.(9 - x)² = 6x² + 243 - 54x + 3x²

Q = 9x² - 54x + 243

Minimize let's derivate:

Q' = 18x - 54 = 0

18x = 54

x = 3

3 + y = 9

y = 9 - 3

y = 6

Q = 6x² + 3y² = 6.3² + 3.6²

Q = 6.9 + 3.36

Q = 162

User Touinta
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8.2k points

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