Answer and Step-by-step explanation:
this is the question then the explanation
A building contractor tendered for two independent contracts, X and Y. The probabilities that he will win contract X is 0.5 and not win contract Y is 0.3, What is the probability that he will win :
(a) both contracts ;
(b) exactly one of the contracts ;
(c) neither of the contracts?
Let A and B denote the events that the man wins contracts X and Y respectively. Then P (A) = 0.5 P (A') = 1 - 0.5 = 0.5 P (B') = 0.3 P (B) = 1 - 0.3 = 0.7 (a) The probability that the man wins both contracts = 0.5 × 0.7 = 0.35.