Question

Let f(x) = -2x-1, h(x) = -x-3. Find (f o h)(6).​

Answer 1

`f(h(6)) = 17`

Explanation:

Given the functions:

`f(x) = -2x-1`,
`h(x) = -x - 3`

we can find the value of
`f(h(6))`, written in the shorthand notation
`(f \circ h)(6)`, with the following steps:

1. plugging 6 into the function
   `h(x)`
2. finding its output
3. plugging the output from
   `h(x)` into the function
   `f(x)`
4. finding its output

↓ plugging 6 in for x in the function
`h(x)`

`h(6) = -6 - 3`

↓ simplifying to find the output

`h(6) = -9`

↓ plugging the output from
`h(6)` in for x in the function
`f(x)`

`f(h(6)) = -2(-9) - 1`

↓ simplifying to find the output

`f(h(6)) = 18 - 1`

`\boxed{f(h(6)) = 17}`