How much heat (in calories) must be applied to a 100 mL beaker filled with boiling water in order to vaporize the water?

Question

asked Mar 22, 2024 89.9k views

1 Answer

Massquote · Answer 1 · 2024-03-26T19:51:55+0000

The latent heat of vaporization of water is 540 Cal/g/°c.

Given amount of water = 100ml

density of water = 1g/ml = 100g

therefore, 540cal/g/ °c×100g= 54,000 Cal

hence, the answer is 5.4×10^4 cal.