Question

A ball of 500 g falls from a certain height into a shallow quicksand below. If the ball takes 2 second to reach the quicksand and

gets embedded in it, calculate the heat energy produced in the process (1 cal = 4.186 J).
O1 cal
O 18 cal
O 23 cal
O 12 cal

Answer 1

Answer: the heat energy produced in the process is approxi 23 cal

Step-by-step explanation:

Potential Energy = mass × acceleration due to gravity × height

Given:

Mass of the ball (m) = 500 g = 0.5 kg

Acceleration due to gravity (g) = 9.8 m/s^2 (approximate value on Earth)

Time taken (t) = 2 seconds

Since the ball falls freely under gravity, we can use the equation for distance traveled during free fall:

Height (h) = (1/2) × g × t^2

Plugging in the values, we get:

Height (h) = (1/2) × 9.8 × (2)^2 = 19.6 m

Now, let's calculate the potential energy lost:

Potential Energy = mass × acceleration due to gravity × height

Potential Energy = 0.5 kg × 9.8 m/s^2 × 19.6 m

Potential Energy = 96.04 J

To convert this into calories, we divide by the conversion factor:

Heat Energy = Potential Energy / (1 cal = 4.186 J)

Heat Energy = 96.04 J / 4.186 J

Heat Energy ≈ 23 cal

correct option is O 23 cal.