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What will be the volume of 0.5 mole of carbon dioxide gas at 27°C and 750 mmHg?

User Zenil
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1 Answer

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To calculate the volume of a gas, we can use the ideal gas law equation:

PV = nRT

Where:

P = Pressure

V = Volume

n = Number of moles

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature in Kelvin

First, we need to convert the given temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 27°C + 273.15

T(K) = 300.15 K

Next, we can substitute the given values into the ideal gas law equation and solve for V:

PV = nRT

V = (nRT) / P

Given:

n = 0.5 mole

R = 0.0821 L·atm/(mol·K)

T = 300.15 K

P = 750 mmHg (which can be converted to atm by dividing by 760 mmHg/atm)

P = 750 mmHg / 760 mmHg/atm

P = 0.9868 atm

Substituting the values into the equation:

V = (0.5 mol * 0.0821 L·atm/(mol·K) * 300.15 K) / 0.9868 atm

V ≈ 12.72 L

Therefore, the volume of 0.5 mole of carbon dioxide gas at 27°C and 750 mmHg is approximately 12.72 liters.

User Agnul
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