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F(x)=x^2-3,g(x)x^2-4; find (f.g)(x)

User Thanthu
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2 Answers

4 votes

Given,

F(x) = x^2 -3

g(x) = x^2-4

(f. g) (x) = f(x). g(x)

= (x^2-3) (x^2-4)

= x^4-4x^2-3x^2+12

= x^4-7x^2+12

User SagiLow
by
8.1k points
3 votes

Answer:

g(x2−4)=2x2−7

User Peuge
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