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Determine the moment of inertia in a circular ring about an axis through it center​

User Chan Tzish
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Answer and Explanation:

I = MR^2

The moment of inertia of a circular ring about its axis can be calculated using the formula I = MR^2, where M is the mass of the ring and R is the radius of the ring. This formula applies when the axis of rotation is perpendicular to the plane of the ring and passes through its center.

User LKM
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