Question

if a chemist diluted his 4.0 m stock solution to make a 250 ml of 0.033 m salt solution, how much stock does he need?

Answer 1

2.06 ml of stock solution is required.

Step-by-step explanation:

We can use the relationship:

M1V1 = M2V2,

where M and V are concentration and volume, and 1 and 2 are the initial and final states, respectively.

M1 = 4.0M

V1 = unknown

M2 = 0.033

V2 = 250 ml

M1V1 = M2V2

(4.0M)*(V1) = (0.033M)*(250ml)

V1 = ((0.033M)*(250ml)/4.0M)

V1 = ((0.033)*(250ml)/4.0) [M cancels]

V1 = 2.06 ml