75.6k views
5 votes
A force of 10N acts on a body of 2kg for 3 sec which was at rest (a) Calculate velocity (b) Change in momentum of the body (c) Rate of change of momentum in the body

User Acemtp
by
8.3k points

1 Answer

3 votes

Answer:

(a) To calculate the velocity of the body, we can use the equation:

force = mass x acceleration

where acceleration = change in velocity / time

Rearranging the equation, we get:

acceleration = force / mass

acceleration = 10N / 2kg

acceleration = 5 m/s^2

Now, we can use the equation:

velocity = initial velocity + acceleration x time

Since the body was at rest initially, the initial velocity is 0. Therefore:

velocity = 0 + 5 m/s^2 x 3 s

velocity = 15 m/s

(b) The change in momentum of the body can be calculated using the equation:

change in momentum = final momentum - initial momentum

Since the body was at rest initially, the initial momentum is 0. Therefore:

final momentum = mass x velocity

final momentum = 2 kg x 15 m/s

final momentum = 30 kg m/s

change in momentum = 30 kg m/s - 0

change in momentum = 30 kg m/s

(c) The rate of change of momentum in the body is simply the change in momentum divided by the time taken. Therefore:

rate of change of momentum = change in momentum / time

rate of change of momentum = 30 kg m/s / 3 s

rate of change of momentum = 10 kg m/s^2

So the rate of change of momentum in the body is 10 kg m/s^2.

User Tronum
by
8.6k points