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The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: The digit must be odd. The letters A, E, I, O, and U cannot be used. Letters cannot be used more than once. The number of possible identification codes that can be created with these conditions is

User Amadillu
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5 votes

Answer:

2100

Explanation:

You want to know the number of codes that can consist of an odd digit followed by 2 different letters that do not include A, E, I, O, or U.

Count

There are 5 odd digits, so 5 choices for the first character.

There are 21 allowed letters, so 21 choices for the second character.

After choosing the 2nd character, there remain 20 allowed letters for the third character.

The number of codes can be ...

5×21×20 = 2100

The number of possible codes is 2100.

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User Darryl Noakes
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