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Graph the line passing through (4,6) whose slope is m= -5/2

User Mafick
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2 Answers

5 votes

Equations

Before graphing, I will write the equation in point-slope form:


\large\boxed{y-y_1=m(x-x_1)}

Where m = slope.

So I plug in the data:


\large\textsf{$y-6=-(5)/(2)(x-4)$}

Now we can graph it:


\rule{350}{4}


\frak{-Dream-}

Graph the line passing through (4,6) whose slope is m= -5/2-example-1
User Jprim
by
8.7k points
5 votes

Answer:

y = -5/2x + 16

Explanation:

Graph the line passing through (4,6) whose slope is m= -5/2-example-1
User Vikash
by
7.3k points

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