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a converging lens has a focal length of 5 cm. an object forms a virtual image, which is located at 12 cm to the right of the lens. the image height is 25 mm. what is the distance of the object to the lens?

User Iulia
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1 Answer

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The distance of the object to the lens can be found using the lens formula, which is: 1/f = 1/v - 1/u, Where:
f = focal length of the lens
v = distance of the virtual image from the lens
u = distance of the object from the lens (unknown)


Given: f = 5 cm
v = 12 cm, Let's plug in these values into the lens formula and solve for u:
1/5 = 1/12 - 1/u

To simplify the equation, we need to find the LCD (Least Common Denominator) of the fractions, which is 60. Multiplying all terms by 60:

12 = 5 * 60 - 60 * 5/u

12 = 300 - 300/u

Rearranging the equation:

300/u = 300 - 12

300/u = 288

To find u, we can cross-multiply:

300u = 288

Dividing both sides by 300:

u = 0.96 cm

Therefore, the distance of the object to the lens is approximately 0.96 cm.

User Ashox
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