Question

The shaft of the motor m turns with an angular velocity ω=100(4+t)rad/s, where t is in seconds.

Answer 1

5

Step-by-step explanation:

The angular velocity of shaft E at t = 5 sec is rad A = 0.044m B = 0.205m C = 0.03m D = 0.05m W(effsef) = 0.05m The distance moved up by the block W in t = 5 sec is W_40 + 16E5sec 300 30 mm U = 225 m 50 mm 8350 = 93,577.777 = 0b 6ce = 40 * 0.05m Sico + kol d = d6 Ssucot + 13d Ss40 Bc ( = 856 40066) + Ils) J000 + 50 - 35 577.777(9) - Ov Ooot 1a50 3850 = 57.77 - O5 Sw = Op 6w = 57.77 - Los) Sw 2.888