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a rectangular garden is 5 ft longer than it is wide. its area is 2250 ft 2 . what are its dimensions?

User Crandel
by
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1 Answer

3 votes

Answer:

45 feet by 50 feet

Explanation:

A rectangular garden has an area(A) that is the product of its length (L) and width (W).

We are told that L = W+5 [. . . is 5 feet longer than it is wide]

We also find that Area = 2250 ft^2

Since A = L*W, lets enter what we know:

Area = (Substitute W+5 for L)*W

2250 ft^2 = (W+5)*W

This give us: W^2 + 5W = 2250 ft^2

Rewrite: W^2 + 5W - 2250 = 0

Solve with the quadratic equation.

The solutions are 45 ft and - 50 feet. We can drop the -50 ft option, so we are left with W = 45 feet. Since L=W+5, the length, L, would therefore be 50 feet.

The rectangular garden is 45 by 50 feet.

CHECK

Does 45 by 50 feet give 2250 ft^2 area? YES

Is the length 5 feet longer than the width? YES (50 - 45 = 5 feet)

User AnshBikram
by
8.0k points
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