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Find the equation of the line that is parallel to y=3x-2 and contains the point (2,11)

User Malta
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1 Answer

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Answer:

y = 2x+ 7

Step-by-step explanation:

The equation y=3x-2 is in standard slope-intercept format of y=mx+b, where m is the slope and b is the y-intercept. Therefore, the slope of this given line is 2 (m=2). A parallel line will have the same slope, so lets write what we know so far about the new parallel line:

y = 2x+b

Any value of b will result in a line that is parallel to y=2x-2. But we need a value of b that will shift the line so that it goes through point (2,11). We can either do this by graphing to find what the value of b should be, or we can simply calculate it.

Calculate b by using the given point (2,11) and then solving for b:

y = 2x+b

11 = 2*(2)+b for (2,11)

11 = 4 + b

b = 7

The parallel line that goes through (2,11) is:

y = 2x+ 7

See the attached graph.

Find the equation of the line that is parallel to y=3x-2 and contains the point (2,11)-example-1
User Jan Bluemink
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