Final answer:
In the alpha decay of Californium-252, an alpha particle is emitted, resulting in Curium-248. This decay process decreases the original atom's mass number by 4 and the atomic number by 2.
Step-by-step explanation:
The given radioactive decay problem involves a nucleus of Californium-252 (252Cf) emitting an alpha particle (4He) to form another element. In radioactive decay, especially alpha decay, the mass number decreases by 4 and the atomic number decreases by 2. To balance the nuclear equation, we subtract the mass number and atomic number of the alpha particle from those of the original nucleus.
The balanced equation is as follows:
25298Cf → 24896Cm + 42He
Here, the element that is produced after the alpha decay of Californium-252 is Curium-248 (248Cm).