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An important reaction in visual excitation is the activation of an enzyme that catalyzes the hydrolysis of guanosine triphosphate:GTP+H2O→GDP+Pi (K′25∘C=1.9×105)GTP+H2O→GDP+Pi (K25∘C′=1.9×105) ⇒ this describes the equilibrium constant for the biochemical standard state.PART C:The solution described in part A is allowed to come to equilibrium. What is the final concentration of GTPGTP?PART D:The solution described in part A is allowed to come to equilibrium. What is the final concentration of GDPGDP?PART E:The solution described in part A is allowed to come to equilibrium. What is the final concentration of PiPi?

User Darrarski
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Final answer:

In the given reaction GTP + H2O -> GDP + Pi, the final concentration of GTP, GDP, and Pi at equilibrium can be determined using the equilibrium constant equation. At equilibrium, the ratio of products to reactants is 1.9x10^5. By substituting initial concentrations into the equation, we can solve for the final concentrations of GTP, GDP, and Pi.

Step-by-step explanation:

In the given reaction: GTP + H2O -> GDP + Pi, the equilibrium constant (K) is given as K'25°C = 1.9x105. This indicates that at equilibrium, the ratio of products (GDP + Pi) to reactants (GTP + H2O) is 1.9x105. To determine the final concentration of GTP, GDP, and Pi at equilibrium, we need the initial concentrations.

Let's say the initial concentration of GTP is [GTP]0, and the final concentrations are [GTP], [GDP], and [Pi]. Since the reaction is freely reversible, the concentrations of reactants and products do not change, they simply reach equilibrium.

Using the equilibrium constant equation, we can write: [GDP][Pi] / ([GTP][H2O]) = K'25°C.

Substituting the values, we get: [GDP][Pi] = K'25°C x [GTP][H2O].

At equilibrium, we know that [GDP] + [GTP] and [Pi] + [H2O] will be equal to their respective initial concentrations. Therefore, we can substitute these values into the equation to get:

[GDP]0 + [GTP] = [GDP] and [Pi]0 + [H2O] = [Pi].

Substituting these values into the equation, we have:

[GDP]0 + [GTP] x [Pi]0 + [H2O] = K'25°C x [GTP][H2O].

Simplifying the equation further, we get:

[GDP]0[Pi]0 = K'25°C x [GTP]0.

From this equation, we can solve for [GTP] which is the final concentration of GTP at equilibrium.

PART C: The final concentration of GTP is [GTP].

PART D: The final concentration of GDP is [GDP] = [GTP]0.

PART E: The final concentration of Pi is [Pi] = [Pi]0.

User GRESPL Nagpur
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