Question

calculate the moment of inertia for a hollow sphere with radius 0.048 m and mass 0.43 kg. express your answer in si units

Answer 1

The moment of inertia (I) for a hollow sphere can be calculated using the formula:

I = (2/3) * m * r^2

where m is the mass and r is the radius of the hollow sphere.

Given:

Radius (r) = 0.048 m

Mass (m) = 0.43 kg

Using the formula, we can substitute the values:

I = (2/3) * 0.43 kg * (0.048 m)^2

Simplifying the equation:

I = (2/3) * 0.43 kg * (0.048 m * 0.048 m)

I = (2/3) * 0.43 kg * 0.002304 m^2

I = 0.00152896 kg * m^2

Therefore, the moment of inertia for the hollow sphere with a radius of 0.048 m and mass of 0.43 kg is approximately 0.00152896 kg * m^2, expressed in SI units.

keywords- Moment of inertia

Answer 2

The moment of inertia (I) for a hollow sphere can be calculated using the formula:

I = (2/3) * m * r^2

where m is the mass and r is the radius of the hollow sphere.

Given:

Radius (r) = 0.048 m

Mass (m) = 0.43 kg

Using the formula, we can substitute the values:

I = (2/3) * 0.43 kg * (0.048 m)^2

Simplifying the equation:

I = (2/3) * 0.43 kg * (0.048 m * 0.048 m)

I = (2/3) * 0.43 kg * 0.002304 m^2

I = 0.00152896 kg * m^2

Therefore, the moment of inertia for the hollow sphere with a radius of 0.048 m and mass of 0.43 kg is approximately 0.00152896 kg * m^2, expressed in SI units.