Answer:
yellow frequency=70%, white frequency=30%, percentage of heterozygotes=42%
Step-by-step explanation:
IM HIMM
start with the homozygous recessive percentage if given, which equals q^2.
The frequency of the yellow kernel recessive genotype ww is 9/10 or q^2
q= srq^2 = sr0.09 = 0.30 = the frequency of w
and p+q=1 thus, p=1-q = 1-0.30= 0.70 = the frequency of W
b) the heterozygotes = 2pq = 2(0.70)(0.30) = 0.42 or 42%