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as the capacitor charges, when the current in the resistor is 0.850 a , what is the magnitude of the charge on each plate of the capacitor?

User Shaul
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1 Answer

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We are given:

- Current in the resistor is 0.850 A

- We need to find the magnitude of charge on each plate of the capacitor

Since the capacitor is charging, current will be flowing through the resistor into the capacitor. By Kirchhoff's current law, the current into and out of a junction are equal. Thus, the 0.850 A current flowing through the resistor will also be charging the capacitor.

The current flowing into a capacitor is equal to the rate of change of charge on the capacitor plates:

I = dq/dt

Where:

I = Current (A)

q = Charge (C)

dt = change in time

Since the current is given as 0.850 A, we can find the charge accumulated on each plate in 1 second.

The charge accumulated in 1 second will be:

q = I * t

= 0.850 A * 1 s

= 0.850 C

So the magnitude of charge on each plate of the capacitor will be 0.850 C.

Therefore, the answer is: 0.850 C