Question

(03. 01 HC) Coordinate plane with quadrilaterals EFGH and E prime F prime G prime H prime at E 0 comma 1, F 1 comma 1, G 2 comma 0, H 0 comma 0, E prime negative 1 comma 2, F prime 1 comma 2, G prime 3 comma 0, and H prime negative 1 comma 0. F and H are connected by a segment, and F prime and H prime are also connected by a segment. Quadrilateral EFGH was dilated by a scale factor of 2 from the center (1, 0) to create E'F'G'H'. Which characteristic of dilations compares segment E'F' to segment EF?

Answer 1

Segment E'F' is twice as long as segment EF because quadrilateral EFGH was dilated by a scale factor of 2 to create E'F'G'H'.

Step-by-step explanation:

The characteristic of dilations that compares segment E'F' to segment EF is that they are proportional to each other by the given scale factor.

Since the quadrilateral EFGH was dilated by a scale factor of 2 from the center (1, 0) to create E'F'G'H', the lengths of corresponding sides of the two quadrilaterals are proportional by this scale factor.

Therefore, segment E'F' is exactly twice as long as segment EF, assuming that the dilation was performed correctly.

The complete question is:(03. 01 HC) Coordinate plane with quadrilaterals EFGH and E prime F prime G prime H prime at E 0 comma 1, F 1 comma 1, G 2 comma 0, H 0 comma 0, E prime negative 1 comma 2, F prime 1 comma 2, G prime 3 comma 0, and H prime negative 1 comma 0. F and H are connected by a segment, and F prime and H prime are also connected by a segment. Quadrilateral EFGH was dilated by a scale factor of 2 from the center (1, 0) to create E'F'G'H'. Which characteristic of dilations compares segment E'F' to segment EF? is:

Answer 2

To compare segment E'F' to segment EF, calculate the length of EF and multiply it by 2 to find the length of E'F'.

Step-by-step explanation:

To compare the segment E'F' to segment EF, we can calculate the length of each segment and compare their ratio. The scale factor of the dilation is 2, which means each side of E'F' is twice as long as the corresponding side of EF. So, if we calculate the length of segment EF and multiply it by 2, we will get the length of segment E'F'. For example, the length of EF is the distance between points E and F, which is 1 unit. Multiplying this by 2 gives us a length of 2 units for segment E'F'.