The Perimeter of ΔA'B'C' is 52 cm.
How did we get the value?
The perimeter of ΔABC is = 13 cm
Length of OB = 5 cm
Length of OB' = 15 + 5
= 20 cm
The Dilation factor can be found out by the division of ΔOCB and ΔOC'B'
From triangles ΔOCB & ΔOC'B' the dilation factor can be found out by the formula below:
BC/B'C'
BC/B'C' = 5/20
Consequently, the dilation factor = 4
Therefore, the new perimeter of the triangle is 13 x 4 = 52 cm