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What is the perimeter of δa'b'c'? 13 cm 26 cm 39 cm 52 cm

User Amir Molaa
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The Perimeter of ΔA'B'C' is 52 cm.

How did we get the value?

The perimeter of ΔABC is = 13 cm

Length of OB = 5 cm

Length of OB' = 15 + 5

= 20 cm

The Dilation factor can be found out by the division of ΔOCB and ΔOC'B'

From triangles ΔOCB & ΔOC'B' the dilation factor can be found out by the formula below:

BC/B'C'

BC/B'C' = 5/20

Consequently, the dilation factor = 4

Therefore, the new perimeter of the triangle is 13 x 4 = 52 cm

What is the perimeter of δa'b'c'? 13 cm 26 cm 39 cm 52 cm-example-1

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